# Steady-state — Welcome to LS-DYNA Examples

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On the basis of a simple wall construction consisting of a concrete wall with insulation, a stationary thermal calculation is carried out. Different temperatures are applied to the inner and outer wall surface.

## Keywords

```*BOUNDARY_TEMPERATURE_SET
*CONTROL_SOLUTION
*CONTROL_TERMINATION
*CONTROL_THERMAL_SOLVER
*DATABASE_BINARY_D3PLOT
*DATABASE_TPRINT
*ELEMENT_SOLID
*END
*INCLUDE
*INITIAL_TEMPERATURE_SET
*KEYWORD
*MAT_THERMAL_ISOTROPIC
*NODE
*PART
*SECTION_SOLID
*SET_NODE_LIST_TITLE
*TITLE```

## Reduced Input

```*KEYWORD
\$
\$=============================CONTROL DEFINITIONS ==============================
\$
*TITLE
steady-state heat transfer through an insulated concrete wall
*CONTROL_SOLUTION
\$ thermal only
\$     soln       nlq     isnan     lcint     lcacc     ncdcf
1
*CONTROL_THERMAL_SOLVER
\$    atype     ptype    solver     cgtol       gpt    eqheat     fwork       sbc
0         0         1
*CONTROL_TERMINATION
\$   endtim    endcyc     dtmin    endeng    endmas     nosol
1.
\$
\$================================ OUTPUTDATA ===================================
\$
*DATABASE_BINARY_D3PLOT
\$       dt
1.0
*DATABASE_GLSTAT
\$       dt
1.0
*DATABASE_MATSUM
\$       dt
1.0
*DATABASE_TPRINT
\$       dt
1.0
\$
\$============================== PART DEFINITIONS ===============================
\$
*PART
\$ title
concrete
\$      pid     secid       mid     eosid      hgid      grav    adpopt      tmid
1         1         0         0         0         0         0         1
*PART
\$ title
insulation
\$      pid     secid       mid     eosid      hgid      grav    adpopt      tmid
2         1         0         0         0         0         0         2
\$
\$============================= SECTION PROPERTIES ==============================
\$
*SECTION_SOLID
\$    secid    elform
1         1
\$
\$======================== THERMAL MATERIAL PROPERTIES ==========================
\$
*MAT_THERMAL_ISOTROPIC
\$ material concrete
\$     tmid       tro     tgrlc    tgmult      tlat      hlat
1    2.4e-9
\$       hc        tc
8.80e8       2.1
*MAT_THERMAL_ISOTROPIC
\$ material insulation
\$     tmid       tro     tgrlc    tgmult      tlat      hlat
2   1.0e-10
\$       hc        tc
9.0e8      0.04
\$
\$======================== NODE/ELEMENT/SET DEFINTIONS ==========================
\$
*INCLUDE
01_insulated_concrete_wall_parts.k
*SET_NODE_LIST_TITLE
inside
\$      sid       da1       da2       da3       da4    solver
1       0.0       0.0       0.0       0.0MECH
\$     nid1      nid2      nid3      nid4      nid5      nid6      nid7      nid8
22         1        64        85        43       106       127       148
169         0         0         0         0         0         0         0
*SET_NODE_LIST_TITLE
outside
\$      sid       da1       da2       da3       da4    solver
2       0.0       0.0       0.0       0.0MECH
\$     nid1      nid2      nid3      nid4      nid5      nid6      nid7      nid8
394       230       271       353       312       435       517       476
558         0         0         0         0         0         0         0
\$
\$==================== THERMAL BOUNDARY and INITIAL CONDITIONS ==================
\$
*INITIAL_TEMPERATURE_SET
\$  nid/sid      temp       loc
0    293.15
*BOUNDARY_TEMPERATURE_SET
\$  nid/sid     tlcid     tmult       loc    tdeath    tbirth
1         0      20.0
2         0      10.0
\$
*END```